How do you graph #y=-x^2+x+12#?
1 Answer
The graph looks like this: graph{-x^2+x+12 [-5, 5, -20, 20]}.
Explanation:
Because there is an
Because the
First, to find out where the parabola crosses the
Next, let's find the two places where the graph intersects the
So the parabola crosses the
-- (0, 12) -- where it crosses the
-- (4, 0) -- one of the
-- (-3, 0) -- other
So that should be enough information to draw the graph.