Question

How do you factor `-3xy^6 + 3xy^2`?

Answer 1

It is `3xy^2(1-y)(1+y)(1+y^2)`

Explanation:

We have that

`-3xy^6+3xy^2=>3xy^2(-y^4+1)=>3xy^2(1-y^2)(1+y^2)=>3xy^2(1-y)(1+y)(1+y^2)`