The length of a rectangle is twice its width. If the perimeter of the rectangle is 42 yd how do you find its area?

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Answer 1 · 2015-09-13T09:55:01

The area of the rectangle is 98.

Given the length and width, the perimeter of the rectangle is=#2(l+w)#

Length is twice its width so #l=2w#

Then-
#2(2w+w)=42yd#
#6w=42yd#
#w=42/6=7#
#l=2w =2 xx 7=14#
The area of the rectangle is #=length xx width =14 xx 7=98#