How do you solve the inequality $- 8 \leq 1 - 3 (x - 2) < 13$ $-8<=1 -3(x-2) < 13$ ?

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Answer 1 · 2015-09-15T03:00:11

$] - 2, 5]$ $]-2, 5]$

$- 8 \leq 1 - 3 (x - 2) < 13$ $−8≤1−3(x−2)<13$

$- 9 \leq - 3 x + 6 < 12$ $-9 <= -3x + 6 < 12$

$- 15 \leq - 3 x < 6$ $-15 <= -3x < 6$

$5 \geq x > - 2$ $5 >= x > -2$

How do you solve the inequality -8<=1 -3(x-2) < 13−8≤1−3(x−2)<13-8<=1 -3(x-2) < 13?