Question

How do you find the derivative for `Y=(2x^7+3x)/(X^3-8)`?

Answer 1

`d/dx[(2x^7+3x)/(x^3-8)]=((x^3-8)(14x+3)-(2x^7+3x)(3x^2))/(x^3-8)^2`

Explanation:

The quotient rule states that the derivative of a quotient of 2 functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by he square of the denominator.

`therefored/dx[(2x^7+3x)/(x^3-8)]=((x^3-8)(14x+3)-(2x^7+3x)(3x^2))/(x^3-8)^2`