Question

How do you factor `p(x)= 2x^3-x^2-18x+9`?

Answer 1

`(x-3)(x+3)(2x-1)`

Explanation:

`p(x)=2x^3−x^2−18x+9`

`=x^2(2x - 1) -9(2x-1)`

`=(x^2-9)(2x-1)`

`=(x-3)(x+3)(2x-1)`