How do you graph #f(x) =-3abs(x+2)+2#?
2 Answers
Explanation:
graph{-3|x+2|+2 [-11.24, 11.26, -5.625, 5.63]}
f(x)=-3|x-2|+2=0
|x-2|=2/3
=>x-2=2/3, -(x-2)=2/3
x=8/3r x=4/3
You can graph it step by step.
Explanation:
Firstly, let's graph the absolute term
When we give values to
graph{|x + 2| [-4.093, 0.907, -0.41, 2.09]}
You can see that
Then, we must consider the coefficient of
graph{-3|x+2| [-4.175, 0.825, -2.42, 0.08]}
The final part is adding the last term of function. The term
Finally, we have:
graph{-3|x+2|+2 [-6.893, 3.107, -2.49, 2.51]}