How do I find the vertex, axis of symmetry, y-intercept, x-intercept, domain and range of y=2(x+3)^2+6?

1 Answer
Sep 25, 2015

Vertex (-3,6),axis of symmetry x= -3,domain is R(set of real numbers) and Range is [6,infinite) graph{2(x+3)^2 +6 [-25.09, 20.51, -2.37, 20.43]}

Explanation:

On simplifying the equation,we have (y-6)/2 = (x+3)^2
which represents a parabola.
Using (y-6)/2 = 0,y=6
and (x+3)^2 = 0,x=-3
Thus,vertex of parabola is (-3,6)
Moreover,it is symmetric about its axis x+3=0