How do you factor $f (x) = x^{3} - 2 x^{2} + 3$ $f(x)=x^3-2x^2+3$ ?

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How do you factor $f (x) = x^{3} - 2 x^{2} + 3$ $f(x)=x^3-2x^2+3$ ?

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Answer 1 · 2015-09-26T08:37:59

$(x + 1) (x^{2} - 3 x + 3)$ $(x+1)(x^2 -3x+3)$

Explanation:

For x=-1, f(-1)=0 , hence x+1 is a factor of f(x). Now divide f(x) by x+1, synthetic or long division, the quotient would come out to be $x^{2} - 3 x + 3$ $x^2-3x+3$ . The factors of f(x) are $(x + 1) (x^{2} - 3 x + 3)$ $(x+1)(x^2 -3x+3)$

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How do you factor $f (x) = x^{3} - 2 x^{2} + 3$ $f(x)=x^3-2x^2+3$ ?

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Explanation:

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