How do you divide (2x^3-x^2+5)÷(x-2)?

1 Answer

Quotient = 2*x^2+3*x+6
Remainder = 17

Explanation:

Without omitting any degrees of the polynomial, the dividend is 2*x^3 - x^2 + 0*x + 5 and the divisor is x - 2
Now using the long division method step by step
Q = quotient
R = remainder
Q0 = 0
R0 = 2*x^3 - x^2 + 0*x + 5
Q1 = 2*x^2
R1 = +3x^2+0*x+5
Q2 = 2*x^2+3x
R2 = +6*x+5
Q3 = 2*x^2+3*x+6
R3 = 17