How do you find the y intercept for #y = x^2 - 4x + 4#?

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Answer 1 · 2015-09-28T00:01:51

The y-intercept is #4#.

The y-intercept is the value of #y# when #x=0#. Therefore, substitute #0# for #x#, and solve for #y#.

#y=x^2-4x+4#

#y=0^2-4(0)+4=#

#y=4#.

Answer 2 · 2015-09-28T00:06:05

Y intercept is 4.

To find the Y-intercept, find the value of this function at #x=0#

#y=x^2−4x+4#
At #x=0; y =(0^2)-(4.0)+4 = 4#

At #(0, 4)# the curve cuts the Y-axis.