Question

How do you simplify `root3( 64y^7 )`?

Answer 1

`root(3)(64y^7) = 4y^2root(3)(y)`

Explanation:

`root(3)(64y^7)`
`color(white)("XXX")=root(3)(64)*root(3)(y^7)`

`color(white)("XXX")=root(3)(4^3)*root(3)((y^2)^3*y)`

`color(white)("XXX")=4*root(3)((y^2)^3)*root(3)(y)`

`color(white)("XXX")=4y^2root(3)(y)`