Question

How do you solve `10x^2 + 19x + 6 = 0` by factoring?

Answer 1

We have that

`10x^2+19x+6=0=>10x^2+4x+15x+6=0=>2x(5x+2)+3(5x+2)=0=>(2x+3)*(5x+2)=0=>x=-3/2 or x=-2/5`