Question

How do you factor `27-t^3`?

Answer 1

`(3-t)(9+3t+t^2)`

Explanation:

`27-t^3=>` use difference of cubes formula:

`a^3-b^3=(a-b)(a^2+ab+b^2)=>` so in this case we have:

`(3^3-t^3)=(3-t)(9+3t+t^2)`