How do you solve #sqrt(x+2)=4#?

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Answer 1 · 2015-10-09T16:13:10

#x=14#

In order to solve this problem, we need to get rid of the square root on the left side. To do this, we square both sides:

#sqrt(x+2) = 4#
#x+2 = 16#

From here we need to get the variable alone. To do this we need to subtract 2 from both sides.

#x+2 = 16#
#x=14#

We then come to our answer.
Hope this helped!

Answer 2 · 2015-10-09T16:14:53

Answer is 14

#sqrt (X+2) = 4#

Square both sides

#(sqrt(( X+2)))^2 = 4^2#

X +2 = 16

Rearrange equations by taking constant from left hand side to right hand side

X = 16-2 =
14