How do you solve #2x^2-13x+15=0# by factoring?

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Answer 1 · 2015-10-11T17:35:26

(2x-3)(x-5)

Split the middle term coefficient -13 so that the product of twp parts is 15*2= 30

13 can thus be split as -3-10, Accordingly,

#2x^2 -13x +15#

=#2x^2 -3x -10x+15#

=#(2x^2 -3x) - (10x-15)#

=#x(2x-3) -5(2x-3)#

=#(2x-3)(x-5)#