Question

How do you rewrite `((a^-2b^5)/c^-3)^-2` using a positive exponent?

Answer 1

`=(a^4)/(b^(10)c^6)`

Explanation:

According to the laws of exponents :

`x^(-n)=1/(x^n)` and `(xy)^n=x^ny^n`

Hence, `((a^(-2)b^5)/(c^(-3)))^(-2)=((b^5c^3)/a^2)^(-2)`

`=(b^(-10)c^(-6))/(a^(-4)`

`=(a^4)/(b^(10)c^6)`