How do you determine whether a linear system has one solution, many solutions, or no solution when given y = 4x + 4 and 3x + 2y = 12?
1 Answer
Here's what you could do.
Explanation:
Your starting equations are
#{ (y = 4x + 4), (3x + 2y = 12) :}#
Now, you can either solve this system and see if you get an unique pair of value for
Alternatively, you can write these equations in slope-intercept form and compare their slopes and
Let's say you want to use both methods.
- Find the two values of
#x# and#y# by solving the system
The first thing to do here is rearrange them so that the
#{(-4x + y = color(white)(x)4), (color(white)(x)3x + 2y = 12) :}#
At this point, you have some options to chose from. You can use the substitution method or the elimination method. I'll use the latter.
Notice that if you multiply the first equation by
This will allow you to find the value of
#{(-4x + y = color(white)(x)4 | xx (-2)), (color(white)(x)3x + 2y = 12) :}#
#{(color(white)(x)8x -2y = -8), (color(white)(x)3x + 2y = 12) :}#
#color(white)(x)stackrel("-------------------------------------")#
#8x - color(red)(cancel(color(black)(-2y))) + 3x + color(red)(cancel(color(black)(-2y))) = -8 + 12#
#11x = 4 implies x = 4/11#
This means that
#y = 4 * (4/11) + 4 = 60/11#
Since solving the system produces an unique value of
- Use slope-intercept form
The slope-intercept form of a line is given by the equation
#color(blue)(y = mx + b)" "# , where
In your case, the first equation is already written in slope-intercept form
#y = 4x + 4 implies {(m = 4), (b = 4) :}#
The second equation's slope-intercept form will be
#2y = -3x + 12#
#y = -3/2x + 6 implies {(m = -3/2), (b = 6) :}#
Because the two lines have different slopes, it follows that they will intersect in one point. Once again, this implies that the system of equations has one solution.
graph{(4x - y + 4)(3x + 2y - 12) = 0 [-10, 10, -2, 10]}