What is the slope and intercept for #y=1/4x# and how would you graph it?

1 Answer
Oct 15, 2015

Slope: #1/4#
y-intercept: #0#
(see below for graph)

Explanation:

The slope-intercept form of a linear equation is
#color(white)("XXX")y=color(red)(m)x+color(blue)(b)#
#color(white)("XXXXXX")#where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept.

#y=1/4x hArr y=color(red)(1/4)x+color(blue)(0)#

#rarr # slope #=color(red)(1/4)# and y-intercept #=0#

Since the y-intercept is #0#
the line goes through the point #(0,0)#
and substituting some multiple of #4# (e.g. #8#) for #x#we can easily determine a second point (in this case #(8,2)#)

Plot these two points on the Cartesian plane and draw a line through them for the required graph.
graph{(y-x/4)(x^2+y^2-0.01)((x-8)^2+(y-2)^2-0.01)=0 [-1.885, 13.915, -3.42, 4.48]}