How do you graph the inequality #4x+6y>=10#?

1 Answer
Oct 18, 2015

Refer to the explanation.

Explanation:

#4x+6y>=10# is in the standard form for a linear equation. Solve for #y# to convert to the slope-intercept form, #y=mx+b#, where #m# is the slope and #b# is the y-intercept.

#4x+6y>=10#

Subtract #4x# from both sides.

#6y>=10-4x#

Divide both sides by #6#.

#y>=10/6-4/6x#

Simplify.

#y>=5/3-2/3x#

Rearrange.

#y>=-2/3x+5/3#

Determine 2 points on the line. Then plot the points and draw a straight solid line through the points to indicate that the line is part of the graph. Then shade the graph above the line.

#x=0,# #y=5/3#

#x=2,# #y=1/3#

graph{y>=-2/3x+5/3 [-10, 10, -5, 5]}