How do you find all the real cube roots of 8/125?
1 Answer
Oct 19, 2015
Explanation:
#8 = 2^3# and#125 = 5^3#
So
#root(3)(8/125) = root(3)(2^3/125^3) = root(3)(2^3)/root(3)(5^3) = 2/5#
The other two roots are both Complex:
#2/5 omega = 2/5((-1+i sqrt(3))/2) = (-1+i sqrt(3))/5#
#2/5 omega^2 = 2/5((-1+i sqrt(3))/2) = (-1-i sqrt(3))/5#
where