Question

What does `(6+4i)/(3-i)` equal?

Answer 1

I found: `7/5+9/5i`

Explanation:

In this case you need to first change the denominator into a pure real number; to do that you need to multiply and divide by the complex conjugate of the denominator, i.e.:
`(6+4i)/(3-i)*color(red)((3+i)/(3+i))=`
`((6+4i)(3+i))/(9+1)=` where you used the fact that `i^2=-1`
and:
`(18+6i+12i-4)/10=14/10+18/10i=7/5+9/5i`