How do you simplify #sqrt(48x^11z^10)#?

Question

1537 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-23T16:15:02

#4x^5z^5sqrt(3x)#

First, factor out all the terms to find any perfect squares.

#[1]color(white)(XX)sqrt(48x^11z^10)#

#[2]color(white)(XX)=sqrt((16)(3)(x^10)(x)(z^10))#

#[3]color(white)(XX)=sqrt((4^2)(3)(x^5)^2(x)(z^5)^2)#

Take all the perfect squares out of the radical symbol.

#[4]color(white)(XX)=(4)(x^5)(z^5)sqrt((3)(x))#

#[5]color(white)(XX)=color(blue)(4x^5z^5sqrt(3x)#