Question

How do you solve `16^(d-4)=3^(3-d)`?

Answer 1

`d=(log1769472)/(log48)`

Explanation:

Using laws of exponents we may write this equation as

`16^d*16^(-4)=3^3*3^(-d)`

`therefore(16xx3)^d=3^3*16^4`

Now taking the log on both sides and simplifying we get

`dlog48=log1769472`

`therefore d=(log1769472)/(log48)`