Question

How do you find the derivative of `y = .75e^x + 2 cos x`?

Answer 1

`d/dx(0,75e^x+2cosx)=0,75e^x-2sinx`

Explanation:

By using laws of differentiation for exponential functions and trigonometric functions, we get

`d/dx(0,75e^x+2cosx)=0,75e^x-2sinx`