Question

What are the important points needed to graph `F(x) = (x-7)^2-3`?

Answer 1

Refer Explanation

Explanation:

`y=(x-7)^2-3`

Its vertex is -

x co-ordinate of the vertex is `-(-7)=7`
y co-ordinate of the vertex is `-3)`

At `(7, - 3)` the curve turns.

Since `a` is positive, the curve opens upward. It has a minimum at `(7, - 3)`

Take two points on either side of `x=7`.
Find the corresponding `y` values.

x: y
5: 1
6: -2
7: -3
8: -2
9: 1

graph{(x-7)^2-3 [-10, 10, -5, 5]}