Given the functions $g (x) = (2 x) (\frac{1}{2})$ $g(x) = (2x) (1/2)$ , $f (x) = x^{2} + 1$ $f(x) = x^2 + 1$ what is f(g(x))?

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Answer 1 · 2015-10-29T21:25:10

$(f \circ g) (x) = f (g (x)) = f (\frac{2 x}{2}) = f (x) = x^{2} + 1$ $(f@g)(x)=f(g(x))=f((2x)/2)=f(x)=x^2+1$

$(f \circ g) (x) = f (g (x)) = f (\frac{2 x}{2}) = f (x) = x^{2} + 1$ $(f@g)(x)=f(g(x))=f((2x)/2)=f(x)=x^2+1$

Given the functions g(x)=(2x)(12)g(x) = (2x) (1/2), f(x)=x2+1f(x) = x^2 + 1 what is f(g(x))?