Question

How do you solve using elimination of `-2x+3y=-5` and `-x+6y=-1`?

Answer 1

`y=1/3 and x = 3` using elimination.

Explanation:

Elimination involves multiplying one equation to make two variable equal to each other.

When I (or you) look at this equation, we can look at either variable. What I notice is that I can multiply `3y` by `-2` to make them cancel eachother out.
`-1x + 6y = -1" " => -1x + 6y = -1`
`(-2x + 3y = -5)(-2) => 4x - 6y = 10`

As you can can see above, I have lined by each `y` with each other. We can add the top equation from the bottom equation. That will leave us with `3x = 9`. We can simplify to `x = 3`.

Now we can plug `x` into either equation to solve for y. I will use `-1x + 6y = -1`.

`-1(3) + 6y = -1`
`" "-3 + 6y = -1`
`" "6y = 2`
`" "y = 1/3 and x = 3`