How do you find the x and y intercept given (-6, 2) and (-3, 4)?

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Answer 1 · 2015-11-10T18:04:33

x-intercept: $(- 9)$ $(-9)$
y-intercept: $6$ $6$

Assuming the equation form we are looking for is linear
then the slope is constant

Slope between the general point $(x, y)$ $(x,y)$ and $(- 6, 2)$ $(-6,2)$ is the same as between $(- 3, 4)$ $(-3,4)$ and $(- 6, 2)$ $(-6,2)$

$\frac{y - 2}{x + 6} = \frac{4 - 2}{- 3 + 6} = \frac{2}{3}$ $(y-2)/(x+6) = (4-2)/(-3+6) = 2/3$

$\Rightarrow 3 (y - 2) = 2 (x + 6)$ $rArr 3(y-2) = 2(x+6)$

$\Rightarrow 3 y - 6 = 2 x + 12$ $rArr 3y-6 = 2x+12$

$\Rightarrow 3 y = 2 x + 18$ $rArr 3y = 2x+18$

When $y = 0$ $y=0$ (the x-intercept) $3 (0) = 2 x + 18 \to x = - 9$ $3(0)=2x+18 rarr x=-9$

When $x = 0$ $x=0$ (the y-intercept) $3 y = 2 (x) + 18 \to y = 6$ $3y=2(x)+18 rarr y= 6$