Question

How do you find the slope and y intercept for: `x +8y=0`?

Answer 1

Slope: `(-1/8)`
y-intercept: `0`

Explanation:

Method 1
A linear equation in the form:
`color(white)("XXX")Ax+By=C`
the slope is `(-A/B)`
and
the y-intercept can be evaluated by setting `x` to `0` and solving for `y`

For the given equation
`color(white)("XXX")x+8y=0`
the slope is `(-((1))/8) = -1/8`
and with `x=0`
`color(white)("XXX")0+8y=0 rArr y=0`

Method 2
Convert the equation in its given form into slope-intercept form.

`x+8y=0`

`rarr 8y=-x`

`rarr y = -1/8x`

`rarr y = (-1/8)x + 0`
`color(white)("XXX")`which is the slope-intercept form for a linear equation
with slope `(-1/8)` and y-intercept `0`