How do you simplify #i^21 + i^30#?

1 Answer
Nov 13, 2015

#i-1#

Explanation:

Observe that the powers of #i# are cyclic:

#i^0= 1#
#i^1 = i#
#i^2 = -1#
#i^3=-i#
#i^4 = 1#
#...#

So, to find high powers of #i#, we can calculate the modulus #4# Since #21 = 5*4 +1#, and #30 = 7*4 +2#, we have that #i^21=i^1=i#, and #i^30 = i^2 = -1#. So,

#i^21+i^30 = i-1#.