Question

A guy drops a rock from a bridge and it hits the river 3.60s later. How high is the bridge?

Answer 1

The formula that will answer this question is
`d = v_i t + 1/2 a t^2`

Explanation:

The information you have been given:
`v_i` = 0 m/s (the rock was not previously moving)
`t` = 3.60 s
`a = 9.80 m/s^2`, as it is resulting from gravity

Plug these values into your formula. This should give you an answer of 63.50 m.