How do you simplify #( 3 + i ) ( 3 + i )#?

1 Answer
Nov 14, 2015

FOIL and know that #i=sqrt(-1)#, so #i^2=-1#.

Explanation:

If the problem were to simplify #(5+x)(2-x)#, you would get #10+2x-5x-x^2#. This problem uses the same logic, except with complex numbers. (Remember that #i=sqrt(-1)#.)

We must distribute #(3+i)(3+i)#.
We should get: #9+3i+3i+i^2#
Combine like terms: #9+6i+color(red)(i^2)#

Now, it may seem that we have done all we can. However, since #i=sqrt(-1)#, we can say that #color(red)(i^2)=(sqrt(-1))^2=color(red)(-1)#. We can put this back into our simplification.

#9+6i+(color(red)(-1))#

Then, we combine like terms again, leaving us with our final answer:
#color(blue)(8+6i)#