How do you factor completely #4x^2-25#? Algebra Polynomials and Factoring Factoring Completely 1 Answer mason m Nov 15, 2015 #(2x+5)(2x-5)# Explanation: Realize that #4x^2-25# is a difference of squares. Differences of squares, such as #a^2-b^2#, can be factored into #(a+b)(a-b)#. Since #4x^2=(2x)^2# and #25=(5)^2#, we can say that #4x^2-25=color(blue)((2x+5)(2x-5)#. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 14139 views around the world You can reuse this answer Creative Commons License