Question

What is the equation of the parabola with axis intercepts of x=3, x=-4, and y=-2?

Answer 1

`y = 1/6 (x-3)(x+4)`

Explanation:

`y = f(x) = a(x-3)(x+4)`

`-2 = f(0) = a(-3) cdot 4 Rightarrow a = 2/12`