How do you divide #(12x^3-16x^2-27x+36)/ (3x-4)#?
1 Answer
Nov 21, 2015
There are several ways to find:
#(12x^3-16x^2-27x+36)/(3x-4) = 4x^2-9#
Explanation:
We can factor by grouping:
#12x^3-16x^2-27x+36#
#=(12x^3-16x^2)-(27x-36)#
#=4x^2(3x-4)-9(3x-4)#
#=(4x^2-9)(3x-4)#
So:
#(12x^3-16x^2-27x+36)/(3x-4) = 4x^2-9#
Alternatively, we can divide
to find:
#(12x^3-16x^2-27x+36)/(3x-4) = 4x^2-9#
with no remainder.