Question

How do you solve `3^(2x-3) = 27sqrt3`?

Answer 1

`x=3,25`

Explanation:

Using laws of exponents we may write this equation as

`3^(2x)*3^(-3)=3^3*3^(1/2)`

`therefore2x-3=3+1/2`

`thereforex=(6,5)/2=3,25`