How do you solve the following system of equations?: -x – 2y = 12 , 12x+y=8?

1 Answer
Dec 13, 2015

(28/23 , -152/28)#

Explanation:

{(-x-2y=12),(12x+y=8):}

Multiply the first equation by 2, to eliminate y

{(-x-2y=12),(color(red)2*(12x+y=8)):}

=> {(-x-2y= 12), (24 x + 2y = 16):}

=> {(-x cancel(-2y)= 12), (24 x cancel(+ 2y) = 16):}

=> 23x =28

=> (13x)/23= 28/23 => x= 28/23

Substitute x= 28/23 into one of the original equation to solve for y

We will use this one 12x + y = 8

12(28/23) + y = 8

336/23 + y = 184/23

y = 184/23 - 336/23

y = -152/23

Answer :(28/23 , -152/28)