Question

How do you solve `ln sqrt(x+1)=2`?

Answer 1

`x=e^4-1`

Explanation:

`lnsqrt(x+1)=2`

`thereforeln(x+1)^(1/2)=2`

`therefore 1/2ln(x+1)=2`

`thereforeln(x+1)=4`

`therefore(x+1)=e^4`

`thereforex=e^4-1`