How do you simplify #i^100#?

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Answer 1 · 2015-12-19T01:24:18

#i^100 = 1#

#i^100 = (i^2)^50 = (-1)^50 = ((-1)^2)^25 = 1^25 = 1#

Answer 2 · 2015-12-19T01:25:51

#1#

Even powers of #i# are equal to #1#

Odd powers of #i# are equal to plus or minus #i#
The signs alternate