How do you solve using elimination of #x-15y=3# and #3x+y=21#?
2 Answers
Explanation:
Given
[1]
[2]
Eliminate the
#{: ([2],color(white)("XXX"),,"(",3x,+y,"=",21,")"), (3xx[1],color(white)("XXX"),-,"(",3x,-45y,"=",9,")") :}#
[4]
[5]
Eliminate the
#{: ([1],color(white)("XXX"),,"(",x,-15y,"=",3,")"), (15xx[2],color(white)("XXX"),+,"(",45x,+15y,"=",315,")") :}#
[6]
[7]
I found:
Explanation:
We can multiply the first equation by
So:
use this into the first equation: