Question

How do you find the x and y intercepts for `y=x^2 + 4x + 4`?

Answer 1

`x`-intercept @ `x=-2`
`y`-intercept @ `y=4`

Explanation:

Original Equation:
`y=x^2+4x+4`

`x`-intercept
Factor:
`y=(x+2)(x+2)`

Solve:
`x=-2`

`x`-intercept @ `x=-2`

`y`-intercept
Set `x` equal to zero and solve:
`y=(0)^2+4(0)+4`
`y=0+4`
`y=4`

`y`-intercept @ `y=4`