Question

What is the period of `f(t)=sin( ( 4t ) /3 )`?

Answer 1

Period is `(3pi)/2`

Explanation:

Period of function of form `sin(Bx)` is `(2pi)/B`.

Our function is `f(t)=sin((4t)/3)`

On comparing with `sin(Bx)` we get `B=4/3`

The using the rule `(2pi)/B` we get the period as

Period =`(2pi)/(4/3)`

Simplifying we get Period = `(3pi)/2`