Question

If a projectile is shot at an angle of `pi/2` and at a velocity of `17 m/s`, when will it reach its maximum height??

Answer 1

After `1.73"s"`

Explanation:

The launch angle = `pi/2` radians which is `90^@` which means a vertical launch.

`v=u+at`

This becomes:

`0=u-"g"t`

`:.0=17-9.8t`

`:.t=17/9.8=1.73"s"`