How do you factor completely #4ax+3ay+4bx+3by#?
1 Answer
Dec 29, 2015
Factor by grouping to find:
#4ax+3ay+4bx+3by = (a+b)(4x+3y)#
Explanation:
#4ax+3ay+4bx+3by#
#=(4ax+3ay)+(4bx+3by)#
#=a(4x+3y)+b(4x+3y)#
#= (a+b)(4x+3y)#