Question

How do you differentiate the following parametric equation: `x(t)=e^t-t, y(t)=1-t^2`?

Answer 1

`-(2t)/(e^t-1)`

Explanation:

`x'(t)=e^t-1`
`y'(t)=-2t`

The derivative of the parametric equation is

`dy/dx=(y'(t))/(x'(t))=-(2t)/(e^t-1)`