Question

What is the derivative of `f(t) = (e^(t^2)-e^t, 2t^2-t )`?

Answer 1

`dy/dx =(4t-1)/(2te^(t^2))`

Explanation:

`x'(t)=2te^(t^2)`
`y'(t)=4t-1`

The derivative of the parametric equation is

`dy/dx=(y'(t))/(x'(t))=(4t-1)/(2te^(t^2))`