What is the derivative of f(t) = (t^2+1 , e^(1-t) ) ? Calculus Parametric Functions Derivative of Parametric Functions 1 Answer mason m Dec 30, 2015 dy/dx=-(e^(1-t))/(2t) Explanation: x'(t)=2t y'(t)=-e^(1-t) The derivative of the parametric function is dy/dx=(y'(t))/(x'(t))=-(e^(1-t))/(2t) Answer link Related questions How do you find the second derivative of a parametric function? How do you find derivatives of parametric functions? How do you find dy/dx for the curve x=t*sin(t), y=t^2+2 ? How do you find the equation of the tangent to the curve x=t^4+1, y=t^3+t at the point... How do you find (d^2y)/(dx^2) for the curve x=4+t^2, y=t^2+t^3 ? How do you find parametric equations of a tangent line? How do you find parametric equations for the tangent line to the curve with the given parametric... How do you find the equation of a line tangent to the curve at point t=-1 given the parametric... How do you differentiate the following parametric equation: x(t)=t^3-5t, y(t)=(t-3) ? How do you differentiate the following parametric equation: x(t)=lnt, y(t)=(t-3) ? See all questions in Derivative of Parametric Functions Impact of this question 1176 views around the world You can reuse this answer Creative Commons License