Question

What is the derivative of `f(t) = (t^2+1 , e^(1-t) )`?

Answer 1

`dy/dx=-(e^(1-t))/(2t)`

Explanation:

`x'(t)=2t`
`y'(t)=-e^(1-t)`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=-(e^(1-t))/(2t)`