Question

What is the derivative of `f(t) = (t-sint , cost )`?

Answer 1

`dy/dx=sint/(cost-1)`

Explanation:

`x'(t)=1-cost`
`y'(t)=-sint`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(-sint)/(1-cost)=sint/(cost-1)`