Question

How do you differentiate the following parametric equation: `x(t)=t^3-t, y(t)= 1-sint`?

Answer 1

`dy/dx=cost/(1-3t^2)`

Explanation:

`x'(t)=3t^2-1`
`y'(t)=-cost`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(-cost)/(3t^2-1)=cost/(1-3t^2)`